Answer:
[tex](x-3)^{2}+(y+2)^{2}=49[/tex]
Step-by-step explanation:
The center-radius form of the equation of a circle is in the format;
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
with the center being at the point (h, k) and the radius being r units.
We simply plugin the values of the center and radius given in order to determine the equation of the circle;
The equation of the circle with center (3, -2) and radius 7 is;
[tex](x-3)^{2}+(y+2)^{2}=49[/tex]
Answer:
[tex](x-3)^2 + (y+2)^2 = 49[/tex]
Step-by-step explanation:
The general equation of a circle has the following form:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
Where the point (h, k) represents the center of the circle and r represents the radius
In this case we know that the center is (3, -2) and the radius is 7.
Therefore:
[tex]h=3\\k = -2\\r=7[/tex]
Finally the equation of the circle is:
[tex](x-3)^2 + (y-(-2))^2 = 7^2[/tex]
[tex](x-3)^2 + (y+2)^2 = 49[/tex]
