What are the solutions of x2 - 2x + 26 = 0 ?
O
A. x = 5; or x = -5;
B. x = 1+5i or x = 1-5i
C. x = 2 +10; or x = 2 -10;
O
D. * = 2+5; or x = 2-5;
SUBMIT

Respuesta :

Answer:

B

Step-by-step explanation:

Given

x² - 2x + 26 = 0 ← in standard form : ax² + bx + c = 0 : a ≠ 0

with a = 1, b = - 2, c = 26

Use the quadratic formula to solve for x

x = ( - (- 2) ± [tex]\sqrt{(-2)^2-(4(1)(26)}[/tex] ) / 2

  = ( 2 ± [tex]\sqrt{4-104}[/tex] ) / 2

  = ( 2 ± [tex]\sqrt{-100}[/tex] ) / 2

  = ( 2 ± 10i ) / 2

  = 1 ± 5i

Solutions are x = 1 + 5i or x = 1 - 5i → B

Answer:

B.x=1+5i or x=1-5i

Step-by-step explanation:

I took the quiz and I guessed and got it right