Answer:
The measure of angle C is 28°
Step-by-step explanation:
Given the area of triangle ABC is 3√2 square inches.
we have to find the measure of angle A if b=9 m and c=2 m
As area of triangle can be calculated as
[tex]Area=\frac{1}{2}\times b\times c\times \Sin C[/tex]
[tex]3\sqrt2=\frac{1}{2}\times 9\times 2\times \sin C[/tex]
[tex]\sin C=\frac{3\sqrt2 \times 2}{9\times 2}=\frac{\sqrt2}{3}[/tex]
[tex]C=sin^{-1}(\frac{\sqrt2}{3})=28.125\sim 28^{\circ}[/tex]
Option 2 is correct.
