Which transformations have been applied to the graph of f(x) = x2 to produce the graph of g(x) = –5x2 + 100x – 450? Check all that apply.

A.The graph of f(x) = x2 is shifted up 25 units.
B.The graph of f(x) = x2 is shifted up 50 units.
C.The graph of f(x) = x2 is shifted down 950 units.
D.The graph of f(x) = x2 is shifted left 10 units.
E.The graph of f(x) = x2 is shifted right 10 units.
F.The graph of f(x) = x2 is reflected over the x-axis.

Respuesta :

frika

Consider the function [tex] g(x) =-5x^2 + 100x- 450 [/tex]. First you need to simplify it by expressing the perfect square:

[tex] g(x) =-5x^2 + 100x- 450=-5(x^2-20x+90)=-5(x^2-2\cdot x\cdot 10+10^2-10^2+90)=-5((x-10)^2-100+90)=-5(x-10)^2+50. [/tex]

So you get [tex] g(x) =-5(x-10)^2+50 [/tex].

Now you can consider all transformations that have been applied to the graph of [tex] f(x) = x^2 [/tex] to produce the graph of g(x):

  1. translate the graph of the function [tex] f(x) [/tex] right 10 units - this transformation gives you the graph of the function [tex] f_1(x)=(x-10)^2 [/tex];
  2. reflect graph of the function [tex] f_1(x) [/tex] about the x-axis. This transformation gives you the graph of the function [tex] f_2(x)=-(x-10)^2 [/tex];
  3. stretch the graph of the function [tex] f_2(x) [/tex] in the y-direction by multiplying the whole function by 5, then you get the function [tex] f_3(x)=-5(x-10)^2 [/tex];
  4. translate the graph of the function [tex] f_3(x) [/tex] up 50 units, then you get the graph of the function [tex] g(x) =-5(x-10)^2+50 [/tex].

From the algorithm above you can conclude that choices B, E and F are correct.

Answer:

B D E

Step-by-step explanation:

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