Respuesta :
[tex]|\Omega|={_{20}C_3}=\dfrac{20!}{3!17!}=\dfrac{18\cdot19\cdot20}{2\cdot3}=1140\\|A|=1\\\\P(A)=\dfrac{1}{1140}\approx0.09\%[/tex]
Answer:
0.014%
Step-by-step explanation:
To calculate the probability that she chooses that exact songs for the piano recital, you just first calculate the probability of her choosing one of them:
[tex]Probability of 1=\frac{1}{20}=.05[/tex]
This is 5%, now you multipy this with the probability of the second song after this one, since there is one less song, the total number of outcomes should be reduced to 19:
[tex]Probability of 2nd=(.05)(\frac{1}{19}[/tex]
[tex]Probability of 2nd=(0.05)(0.052}[/tex]
[tex]Probability of 2nd=0.002[/tex]
This would be .26%
To calculate the probability of the third song being chosen after the first two, we have 2 less outcomes possibles, so the total number of possibilities now is reduced to 18.
[tex]Probability of 3rd=(.0026)(\frac{1}{18}[/tex]
[tex]Probability of 3rd=(.0026)(0.055)[/tex]
[tex]Probability of 3rd=0.00014[/tex]
The probability of Noam choosing the three songs would be: 0.014%