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A uniform metre rule of mass 200g is pivoted at 0cm mark. Calculate the force which would be applied vertically up at the 60cm mark to keep the rule horizontal​

Respuesta :

MathPhys

Explanation:

There are two forces acting on the ruler: weight pulling down halfway at the 50cm mark, and the upward force at the 60cm mark.

Sum of the moments about the pivot:

∑τ = Iα

F (0.60) − (0.200) (9.8) (0.50) = 0

F = 1.63 N

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