Answer: Last Option
(3, -1)
Step-by-step explanation:
We have the following quadratic function:
[tex]f(x) =(x-3)^2 - 1[/tex]
By definition for a quadratic function in the form:
[tex]f (x) = a (x-h) ^ 2 + k[/tex]
the vertex of the function is always the point (h, k)
Note that for this case the values of h, a, and k are:
[tex]a = 1\\h = 3\\k = -1[/tex]
Therefore the vertex of the function [tex]f(x) =(x-3)^2 - 1[/tex] is the point
(3, -1)
