Answer:
=C₄H₄O₂
Explanation:
Given the empirical formula of a molecule, the he the quotient of the molecular mas and and the empirical mass=constant.
84.0 g/mol/mass of(C₂H₂O)=constant
=84/(12×2+1×2×16)
=84/42
=2
Therefore, the molecular formula is (C₂H₂O)₂=C₄H₄O₂
Answer:
[tex]C_2 H_2 O \times 2=C_4 H_4 O_2[/tex] is the molecular formula
Explanation:
Empirical formula is the simplest form of a Molecular formula.
For example
Molecular formula of glucose is [tex]C_6 H_{12} O_6[/tex]
Its empirical formula is [tex]C_1 H_2 O_1[/tex]
The subscript numbers of the molecular formula is divided by a common number n=6 here.
Another example:
Molecular formula of Octane is [tex]C_8 H_{18}[/tex] and Its empirical formula will be [tex]C_4 H_9[/tex]
Subscripts divided by n=2.
To find n we make use of the formula
[tex]\frac {(molecular mass )}{(empirical formula mass)}=n[/tex]
[tex]= \frac {84.0g}{(C_2H_2O mass)}\\\\=\frac {84.0g}{(24+2+16)g}=\frac {84.0g}{42g}=2[/tex]
So, we see n=2 here
Empirical formula × n = molecular formula
[tex]C_2 H_2 O \times 2=C_4 H_4 O_2[/tex] is the molecular formula
(Answer)
Please note:
Molar mass is the mass of 1 mole of the substance and its unit is g/mol .
n is the number of moles by which the empirical formula is multiplied to get the molecular formula of the compound.
