Respuesta :
[tex]F=\dfrac{9}{5}C+32\\5F=9C+160\\9C=5F-160\\C=\dfrac{5F-160}{9}[/tex]
Answer:
C = (5/9)(F - 32)
Step-by-step explanation:
Please enclose fractional coefficients inside parentheses: F=(9/5)C+32. Solve for C as follows:
1) Multiply all three terms of F=(9/5)C+32 by 5, to eliminate the fractional coefficient (9/5): 5F = 9C + 160
2) Subtract 160 from both sides:
5F - 160 = 9C
3) Divide all three terms by 9, to isolate C:
(5/9)F - (160/9) = C
Simplify:
C = (5/9)(F - 32)
Example/check: If F = 32 (freezing), that temperature is 0 C. Do we get 0 by subbing 32 for F? YES
If F = 212 (boiling), that temperature in degrees C is 100. Do we get 100 by subbing 212 for F? YES