Respuesta :

[tex]F=\dfrac{9}{5}C+32\\5F=9C+160\\9C=5F-160\\C=\dfrac{5F-160}{9}[/tex]

Answer:

C = (5/9)(F - 32)

Step-by-step explanation:

Please enclose fractional coefficients inside parentheses:   F=(9/5)C+32.  Solve for C as follows:

1) Multiply all three terms of F=(9/5)C+32 by 5, to eliminate the fractional coefficient (9/5):  5F = 9C + 160

2) Subtract 160 from both sides:  

5F - 160 = 9C

3) Divide all three terms by 9, to isolate C:

(5/9)F - (160/9) = C

Simplify:  

C = (5/9)(F - 32)

Example/check:  If F = 32 (freezing), that temperature is 0 C.  Do we get 0 by subbing 32 for F?  YES

If F = 212 (boiling), that temperature in degrees C is 100.  Do we get 100 by subbing 212 for F?  YES