Find the equation for the linear function that passes through the points ( see photo)

Answer:
f(x) = (-4/5)*x + 4
Step-by-step explanation:
The line which passes through these points will decrease y by 12 for every x increase of 15. This is the same as decreasing y by 4 for every x increase of 5. This means the slope (rise over run) is -4/5. If this is applied to the first point to find what y is at 0, then the point (0, 4) is on the line.
This means that f(x) = (-4/5)*x + 4
Answer:
[tex]\large\boxed{y=-\dfrac{4}{5}x+4}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-5, 8) and (10, -4). Substitute:
[tex]m=\dfrac{-4-8}{10-(-5)}=\dfrac{-12}{15}=-\dfrac{12:3}{15:3}=-\dfrac{4}{5}[/tex]
Put it to the equation of a line:
[tex]y=-\dfrac{4}{5}x+b[/tex]
Put the coordinates of the point (-5, 8) to the equation, and solveit for b:
[tex]8=-\dfrac{4}{5\!\!\!\!\diagup_1}(-5\!\!\!\!\diagup^1)+b[/tex]
[tex]8=4+b[/tex] subtract 4 from both sides
[tex]4=b\to b=4[/tex]
Finally we have:
[tex]y=-\dfrac{4}{5}x+4[/tex]