The admission fee at an amusement park is $3.50 for children and $7.00 for adults. On a certain day, 331 people entered the park, and the admission fees collected totaled $1,771.00 dollars. How many children and how many adults were admitted?

Question

contestada

Respuesta :

hdawg7797 hdawg7797 · Answer 1 · 2019-07-06T21:22:20+02:00

Let c be children and a adults.

3.5c + 7a = 1771 (the total revenue is equal to the amounts made off of people)

c + a = 331 (total number of people)

The second formula becomes a = 331 - c. This can be substituted into the first formula.

3.5c + 7(331 - c) = 1771 = 7*331 - 3.5c = 1771. 7*331 = 2317, so 3.5c = 2317 - 1771 = 546.

546/3.5 = 156 = c (number of children).

c + a = 156 + a = 331 => a = 331 - 156 = 175 (number of adults).

There are 156 children and 175 adults

luisejr77 luisejr77 · Answer 2 · 2019-07-06T21:33:14+02:00

Answer:

156 children

175 adults

Step-by-step explanation:

Let's call x the number of children admitted and call z the number of adults admitted.

Then we know that:

[tex]x + z = 331[/tex]

We also know that:

[tex]3.50x + 7z = 1,771.00[/tex]

We want to find the value of x and z. Then we solve the system of equations:

-Multiplay the first equation by -7 and add it to the second equation:

[tex]-7x - 7z = -2,317[/tex]

[tex]3.50x + 7z = 1,771[/tex]

----------------------------------

[tex]-3.5x = -546[/tex]

[tex]x =\frac{-546}{-3.5}\\\\x=156[/tex]

Now we substitute the value of x in the first equation and solve for the variable z

[tex]156 + z = 331[/tex]

[tex]z = 331-156[/tex]

[tex]z = 175[/tex]