Respuesta :

konrad509

[tex]\log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log_315-\log_310=\log_3\dfrac{15}{10}=\boxed{\log_3\dfrac{3}{2}}[/tex]

Answer:

B.

Step-by-step explanation:

They have the same base so use the quotient rule (since they have a minus sign in between).

We are using this rule: [tex] log_a(b)-log_a(c)=log_a(\frac{b}{c})[/tex]

So we have  [tex] log_3(15)-log_3(10)=log_3(\frac{15}{10})[/tex]

We can reduce the inside fraction... 15/10=3/2

So the answer is B.

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