What is the length of BC in the right triangle below?

Answer:
Step-by-step explanation:
Use the Pythagorean theorem:
[tex]hypotenuse^2=leg^2+leg^2[/tex]
We have
[tex]leg=AC=36,\ leg=AB=15, hypotenuse=BC[/tex]
Substitute:
[tex]BC^2=36^2+15^2\\\\BC^2=1296+225\\\\BC^2=1521\to BC=\sqrt{1521}\\\\BC=39[/tex]