Identify the equation of the circle Y that passes through (2,6) and has center (3,4).

Answer:
(x − 3)² + (y − 4)² = 5
Step-by-step explanation:
The equation of a circle is:
(x − h)² + (y − k)² = r²
where (h, k) is the center and r is the radius.
First use the distance formula to find the radius:
d² = (x₂ − x₁)² + (y₂ − y₁)²
r² = (2 − 3)² + (6 − 4)²
r² = 1 + 4
r² = 5
Given that (h, k) = (3, 4):
(x − 3)² + (y − 4)² = 5
Answer:
Step-by-step explanation:
Inserting the coordinates of the center (3, 4) into the standard equation of a circle with center at (h, k) and radius r, we get:
(x - 3)^2 + (y - 4)^2 = r^2
Next, we substitute 2 for x, 6 for y and solve the resulting equation for r^2:
(2 - 3)^2 + (6 - 4)^2 = r^2, or
1 + 4 = r^2.
Thus, the radius is √5. Subbing this result into the equation found above, (x - 3)^2 + (y - 4)^2 = r^2, we get:
(x - 3)^2 + (y - 4)^2 = (√5)^2 = 5, which matches the last of the four possible answer choices.