[tex]\frac{3}{4} = log_{2}(\sqrt[4]{8} )\\-4 = log_{3} \frac{1}{81} \\-6= -3log_{5} 25\\\frac{1}{3} = log_{6} (\sqrt[3]{6} )[/tex]
Here's how you solve it!
[tex]log_{2} \sqrt[4]{8}[/tex]
Write it in exponential form
[tex]log_{2} (2 \frac{3}{4} )[/tex]
Then simplify
[tex]\frac{3}{4}[/tex]
[tex]log_{3} \frac{1}{81}[/tex]
Write in exponential form
[tex]log_{3} (3^{-4} )[/tex]
Simplify
-4
[tex]-3log_{5} 25[/tex]
Write in exponential form
[tex]-3log_{5} (5^{2} )[/tex]
Simplify
-3 * 2 = -6
-6
[tex]log_{6} \sqrt[3]{6}[/tex]
Write in exponential form
[tex]log_{6} (6\frac{1}{3} )[/tex]
Simplify
[tex]\frac{1}{3}[/tex]
Hope this helps! :3
