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A cashier has 54 bills, all of which are $10 or $20 bills. The total value of the money is $910. How many of each type of bill
does the cashier have?

Respuesta :

salatulmaghrib
20x + 10(54-x) = 910
x = 37 = number of $20 bills
54-x=54-37=17=number of $10 bills

Answer:

the number of $10 bills = 17

the number of $20 bills = 37

Step-by-step explanation:

Let x be the number of $10 bills  and y be the number of $20 bills

Total bills = 54

So [tex]x+y= 54[/tex]

Total value of money is $910

[tex]10x+20y= 910[/tex]

now we solve for x  and y

Solve the first equation for y

[tex]x+y= 54[/tex]

[tex]y=54-x[/tex]

Now replace y in second equation

[tex]10x+20y= 910[/tex]

[tex]10x+20(54-x)= 910[/tex]

[tex]10x+ 1080-20x= 910[/tex]

[tex]1080-10x= 910[/tex]

Subtract 1080 from both sides

[tex]-10x= -170[/tex]

Divide both sides by -10

x= 17

[tex]y=54-x[/tex]

Replace x with 17

[tex]y=54-17=37[/tex]

the number of $10 bills = 17

the number of $20 bills = 37

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