contestada

If a rectangle's length is
2t+1
and the width is
t-3 write an expression for the perimeter and an expression for the area.

Respuesta :

HazP1z

Answer:

Perimeter = 6t - 4

Area = 2t² - 7t - 3

Step-by-step explanation:

Given length = 2t + 1

Width = t - 3

So perimeter = 2t +1 + t - 3 + 2t + 1 + t - 3

= 2t + t + 2t + t + 1 - 3 + 1 - 3

= 6t - 4

Area = (2t + 1)(t - 7)

= 2t² - 6t + t - 3

= 2t² - 7t - 3

Sorry if im wrong but i think thats the answer

carlosego

For this case we have that by definition:

The area of a rectangle is given by:

[tex]A = a * b[/tex]

Where:

a and b are the sides of the rectangle.

For its part, the perimeter will be given by:

[tex]P = 2a + 2b[/tex]

If we have as data:

[tex]a = 2t + 1\\b = t-3[/tex]

So, the area is given by:

[tex]A = (2t + 1) (t-3)[/tex]

We apply distributive property:

[tex]A=2t^2-6t+t-3\\A=2t^2-5t-3[/tex]

For its part, the perimeter is:

[tex]P = 2 (2t + 1) +2 (t-3)\\P = 4t + 2 + 2t-6\\P = 6t-4[/tex]

ANswer:

[tex]A = 2t ^ 2-5t-3\\P = 6t-4[/tex]

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