Answer:
0.0979 kg/m³
Explanation:
Treating air as an ideal gas:
PV = nRT
n/V = P/RT
Density depends on both pressure and temperature. If we assume the temperature is constant, we can say that density is directly proportional to pressure.
ρ = kP
ρ/P = k
Writing a proportion:
(1.26 kg/m³) / (7720 mmHg) = ρ / (600 mmHg)
ρ = 0.0979 kg/m³
Answer:
[tex]\rho = 0.098 kg/m^3[/tex]
Explanation:
As we know that for ideal gas we will have
[tex]PV = nRT[/tex]
here we can convert it into the form of density
[tex]PV = \frac{m}{M}RT[/tex]
now we have
[tex]PM = \rho RT[/tex]
now if the temperature will remain constant then in that case
[tex]\frac{P}{\rho} = constant[/tex]
so we will have
[tex]\frac{P_1}{P_2} = \frac{\rho_1}{\rho_2}[/tex]
here we can plug in all values in it
[tex]\frac{7720}{600} = \frac{1.26}{\rho}[/tex]
now we have
[tex]\rho = \frac{600}{7720}(1.26)[/tex]
[tex]\rho = 0.098 kg/m^3[/tex]
