An 8.0-ohm resistor and a 6.0-ohm resistor are connected in series with a battery. The potential difference across the 6.0-ohm resistor is measured as 12-V. (a) Find the total resistance of the circuit. (b) Find the current in the 6.0-ohm resistor. (c) Find the potential difference across the battery.

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Respuesta :

(a) The total resistance of the circuit will be 14.0-ohm.

(b) The current in the 6.0-ohm resistor will be 1.5 A.

(c) The potential difference across the battery will be 12-V.

What is a series circuit?

In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.

The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.

(a)

The total resistance of the circuit is found as;

R=R₁+R₂

R=8 -ohm +6-ohm

R=14.0-ohm

(b)

The current in the 6.0-ohm resistor is;

The potential difference across the 6.0-ohm resistor= 12-V.

From Ohm's law;

V=IR

I=V/R

I=12-V/8-ohm

I=1.5-A

c)The potential difference across the battery is;

[tex]\rm I=I_1 \\\\ \frac{V}{R} =\frac{V_1}{R_1} \\\\\frac{V}{14} =\frac{12}{6} \\\\ V=28 \ volt[/tex]

Hence, a) The total resistance of the circuit will be 14.0-ohm.

(b) The current in the 6.0-ohm resistor will be 1.5 A.

(c) The potential difference across the battery will be 12-V.

To learn more about the series circuit, refer to the link;

https://brainly.com/question/11409042

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