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Question 7
(02 04 MC)
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A car manufacturer is reducing the number of incidents with the transmission by issuing a voluntary recall. During week 10 of the recall, the manufacturer fixed 200 cars. In week 15, the manufacturer fixed 175 cars. Assume
that the reduction in the number of cars each week is linear Write an equation in function form to show the number of cars seen each week by the mechanic.
f(x) = 5x + 250
f(x) = -5x+250
f(X) = 10x+200
f(x) = -10x+200

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FelisFelis FelisFelis · Answer 1 · 2019-07-22T12:59:52+02:00

Answer:

The correct option is B) [tex]f(x)=-5x+250[/tex].

Step-by-step explanation:

Consider the provided information.

let x represents the number of weeks and y represents the fixed cars.

During week 10 of the recall, the manufacturer fixed 200 cars.

Thus, the ordered pair can be made with the help of the above data is: (10,200).

In week 15, the manufacturer fixed 175 cars.

Thus, the ordered pair can be made with the help of above data is: (15,175)

Now use two point slope formula: [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Substitute the [tex](x_1,y_1)=(10,200)\ \text{and}\ (x_2,y_2)=(15,175)[/tex] in the above formula.

[tex]y-200=\frac{175-200}{15-10}(x-10)[/tex]

[tex]y-200=\frac{-25}{5}(x-10)[/tex]

[tex]y-200=-5(x-10)[/tex]

[tex]y-200=-5x+50[/tex]

[tex]y=-5x+250[/tex]

Which also can be written as:

[tex]f(x)=-5x+250[/tex]

Hence, the correct option is B) [tex]f(x)=-5x+250[/tex].