Respuesta :
Answer:
Step-by-step explanation:
6x^2+5x+1=0
Descr= b^2-4ac
Descr= 25-24=1
X1= (-b+√descr)/2a = (-5+1)/12= -1/3
X2= (-b-√descr)/2a = (-5-1)/12= -1/2
Answer:
see explanation
Step-by-step explanation:
Given
6x² + 5x + 1 = 0
To factorise the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
The factors are + 3 and + 2
Use these factors to split the x- term
6x² + 3x + 2x + 1 = 0 ← ( factor the first/second and third/fourth terms )
3x(2x + 1) + 1 (2x + 1) = 0 ← factor out (2x + 1) from each term
(2x 1)(3x + 1) = 0
Equate each factor to zero and solve for x
2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - [tex]\frac{1}{2}[/tex]
3x + 1 = 0 ⇒ 3x = - 1 ⇒ x = - [tex]\frac{1}{3}[/tex]
