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An automobile tire has a radius of 0.344 m, and its center moves forward with a linear speed of v = 20.1 m/s. (a) Determine the angular speed of the wheel. (b) Relative to the axle, what is the tangential speed of a point located 0.135 m from the axle?

Respuesta :

Answer:

The angular speed and tangential speed are 58.69 rad/s and 7.92 m/s.

Explanation:

Given that,

Radius = 0.344 m

Speed v= 20.1 m/s

(I). We need to calculate the angular speed

Firstly we will calculate the time

Using formula of time

[tex]t = \dfrac{d}{v}[/tex]

[tex]t=\dfrac{2\pi\times r}{v}[/tex]

[tex]t =\dfrac{2\times3.14\times0.344}{20.1}[/tex]

[tex]t=0.107[/tex]

The angular velocity of the tire

[tex]\omega=\dfrac{2\pi}{t}[/tex]

[tex]\omega=\dfrac{2\times3.14}{0.107}[/tex]

[tex]\omega=58.69\ rad/s[/tex]

Now, using formula of angular velocity

(II). We need to calculate the tangential speed of a point located 0.135 m from the axle

The tangential speed

[tex]v = r\omega[/tex]

Where,

r = distance

[tex]\omega[/tex]= angular velocity

Put the value into the formula

[tex]v= 0.135\times58.69[/tex]

[tex]v=7.92\ m/s[/tex]

Hence, The angular speed and tangential speed are 58.69 rad/s and 7.92 m/s.