Answer:
9.1 x 10⁵ ohm
Explanation:
C = Capacitance of the capacitor = 9 x 10⁻⁶ F
V₀ = Voltage of the battery = 13 Volts
V = Potential difference across the battery after time "t" = 4 Volts
t = time interval = 3 sec
T = Time constant
R = resistance
Potential difference across the battery after time "t" is given as
[tex]V = V_{o} (1-e^{\frac{-t}{T}})[/tex]
[tex]4 = 13 (1-e^{\frac{-3}{T}})[/tex]
T = 8.2 sec
Time constant is given as
T = RC
8.2 = (9 x 10⁻⁶) R
R = 9.1 x 10⁵ ohm
