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A square, single-turn coil 0.132 m on a side is placed with its plane perpendicular to a constant magnetic field. An emf of 27.1 mV is induced in the winding while the area of the coil decreases at a rate of 0.0785 m2 /s. What is the magnitude of the magnetic field? Answer in units of T.

Respuesta :

Answer:

0.35 T

Explanation:

Side, a = 0.132 m, e = 27.1 mV = 0.0271 V, dA / dt = 0.0785 m^2 / s

Use the Faraday's law of electromagnetic induction

e = rate of change of magnetic flux

Let b be the strength of magnetic field.

e = dФ / dt

e = d ( B A) / dt

e = B x dA / dt

0.0271 = B x 0.0785

B = 0.35 T

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