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A model rocket is constructed with a motor that can provide a total impulse of 35.0 N·s. The mass of the rocket is 0.192 kg. What is the speed that this rocket achieves when it is launched from rest? Neglect the effects of gravity and air resistance.

Respuesta :

Answer:

[tex]v_f = 182.3 m/s[/tex]

Explanation:

As we know that total impulse is given as the product of mass and change in velocity

so here we will have

[tex]I = m(\Delta v)[/tex]

here we will have

[tex]I = 35.0 N s[/tex]

also we know that mass of the rocket is

m = 0.192 kg

now we will have

[tex]35 = 0.192(v_f - 0)[/tex]

[tex]v_f = 182.3 m/s[/tex]

ajeigbeibraheem

The speed that the rocket achieves when it is launched from rest by neglecting the effect of gravity, as well as, air resistance is 182.3 m/s

What is the total impulse of an object?

The total impulse of an object is the change in velocity of an object when it is worked upon by a force for a period of time.

From the given information; the total impulse can be expressed by using the formula:

  • I = m ×Δv

where;

  • I = Impulse = 35.0 Ns
  • M = mass = 0.192 kg
  • v = velocity = ??

[tex]\mathbf{I = m (\Delta v)}[/tex]

[tex]\mathbf{35.0 = 0.192 ( v_{finai} - v_{initial})}[/tex]

[tex]\mathbf{35.0 = 0.192 ( v_{final} - 0)}[/tex]

[tex]\mathbf{v_{final} = \dfrac{35}{0.192}}[/tex]

[tex]\mathbf{v_{final} =182.3 \ m/s}[/tex]

Learn more about the impulse of an object here:

https://brainly.com/question/20586658

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