Respuesta :
a. The resistance of the bulb is equal to 4.58 Ohms.
b. The fraction of the chemical energy transformed which appears as internal energy in the batteries is 8.4%.
Given the following data:
- Voltage of battery = 1.5 Volts
- Internal resistance A = 0.240 Ohms
- Internal resistance B = 0.180 Ohms
- Current = 600 mA = 0.6 Amps
a. To find the resistance of the bulb:
First of all, we would determine the total electromotive force (E) of the electric circuit:
[tex]E = 2 \times 1.50[/tex]
E = 3.0 Volts
Total internal resistance = [tex]0.240 + 0.180 = 0.42 \;Ohms[/tex]
Mathematically, electromotive force (E) is given by the formula:
[tex]E = V + Ir[/tex] ....equation 1.
Where:
- E is the electromotive force (E).
- V is the the voltage or potential difference.
- I is the current.
- r is the internal resistance.
According to Ohm's law, voltage is given by:
[tex]V = IR[/tex] ....equation 2
Substituting eqn 2 into eqn 1, we have:
[tex]E = IR + Ir\\\\E = I(R + r)\\\\R + r = \frac{E}{I} \\\\R = \frac{E}{I} - r\\\\R = \frac{3}{0.6} - 0.42\\\\R = 5 - 0.42[/tex]
Resistance, R = 4.58 Ohms
b. To determine what fraction of the chemical energy transformed appears as internal energy in the batteries:
First of all, we would determine the electromotive force (E) in the batteries.
[tex]E_B = IR\\\\E_B = 0.6 \times 0.42[/tex]
[tex]E_B[/tex] = 0.252 Volt
[tex]Percent = \frac{E_B}{E} \times 100\\\\Percent = \frac{0.252}{3} \times 100\\\\Percent = \frac{25.2}{3}[/tex]
Percent = 8.4 %
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