Respuesta :
Answer:
D)the first ionization energy (IE1) of B is most probably lower than the first ionization energy (IE1) of A
Explanation:
As mentioned the possible chemical formula for a compound can be predicted from electron configurations of the elements.
The first element 'A' has electronic configuration as "[core]ns²
It means it has two valence electrons and it can give those valence electrons to attain noble gas or full filled stability.
So the element is most likely to form a dipositive ion.
Now for element B the configuration is :[Core]ns²np⁵
thus it has seven valence electrons and it will most likely to accept an electron to gain full filled stability. So B will form a mono negative ion.
The possible formula will be AB₂ [Like MgCl₂]
So the false statements are:
D)the first ionization energy (IE1) of B is most probably lower than the first ionization energy (IE1) of A : the first ionization energy of A will be lower than B as B cannot give an electron easily.
The other statements are correct:
A) element A serves as the reducing agent in the reaction to form AxBy : As A will lose electrons so it will acts as reducing agent and itself gets oxidized
B) yes it is whole number as calculated above.
C) x + y = 1+2 = 3
E) Already calculated that B has oxidation state of -1.
The false statement is that; "the first ionization energy (IE1) of B is most probably lower than the first ionization energy (IE1) of A"
The first ionization energy is the energy required to remove the first electron from an atom. This is a periodic trend that increases across the period but decreases down the group.
Looking at the electron configurations of A and B it is clear that A is an alkaline earth metal while B is a halogen. As such, A is a reducing agent and B will have an oxidation state of -1 as expected of halogens.
The compound will have the formula AX2 hence x + y = 3. However, since ionization energy increases across the period, the first ionization energy of B must certainly be greater than that of A.
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