Answer:
The yearly release of [tex]CO_2[/tex] into the atmosphere is [tex]6.73\times 10^{10} kg[/tex].
Explanation:
[tex]CaCO_3(s)\rightarrow CaO(s) + CO_2(g)[/tex]
Annual production of CaO = [tex]8.6\times 10^{10} kg=8.6\times 10^{13} g[/tex]
Moles of CaO :
[tex]\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles[/tex]
According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.
Then along with [tex]1.53\times 10^{12} moles[/tex] of CaO moles of carbon-dioxide moles produced will be:
[tex]\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles[/tex] of carbon-dioxide
Mass of [tex]1.53\times 10^{12}[/tex] moles of carbon-dioxide:
[tex]1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg[/tex]
The yearly release of [tex]CO_2[/tex] into the atmosphere is [tex]6.73\times 10^{10} kg[/tex].
