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A national random sample of 654 women aged 20 – 29 years was taken, and each woman's body mass index (BMI) was measured. The sample data had mean BMI ????¯=26.8 and standard deviation ????=7.42 . What is the 95% ???? confidence interval (????,????) for the mean BMI of all young women?

Respuesta :

Answer:

The required interval is (26.23 , 27.37)

Step-by-step explanation:

The mean is = 26.8

The standard deviation is = 7.42

n = 654

At 95% confidence interval, the z score is 1.96

To find the desired interval we will calculate as:

[tex]26.8+1.96(\frac{7.42}{\sqrt{654} } )[/tex]

And [tex]26.8-1.96(\frac{7.42}{\sqrt{654} } )[/tex]

[tex]26.8+0.57[/tex] and [tex]26.8-0.57[/tex]

= 27.37 and 26.23

So, the required interval is (26.23 , 27.37)

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