Respuesta :
Answer:
6.3 sec
Explanation:
x = distance after which first-place bicyclist is caught
t = time taken to get caught
Consider the motion of the first-place bicyclist :
x = distance traveled by first-place bicyclist
t = time of travel
v = velocity = 11.9 m/s
distance traveled by first-place bicyclist is given as
x = v t
x = 11.9 t eq-1
d = distance between first and second place bicyclist = 10.6 m
Consider the motion of the second-place bicyclist :
x' = distance traveled by first-place bicyclist = x + d = x + 10.6
t = time of travel
a = acceleration = 1.20 m/s²
v₀ = initial velocity = 9.80 m/s
Using the equation
x' = v₀ t + (0.5) a t²
x + 10.6 = 9.80 t + (0.5) (1.20) t²
using eq-1
11.9 t + 10.6 = 9.80 t + (0.5) (1.20) t²
t = 6.3 sec
