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A 14-Ω coffee maker and a 14-Ω frying pan are connected in series across a 120-V source of voltage. A 20-Ω bread maker is also connected across the 120-V source and is in parallel with the series combination. Find the total current supplied by the source of voltage.

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Answer:

The total current supplied by the source of voltage = 10.29 A

Explanation:

We have a 14-Ω coffee maker and a 14-Ω frying pan are connected in series.

Effective resistance = 14 + 14 = 28Ω

Now we have 28Ω and 20Ω in parallel

Effective resistance

             [tex]R=\frac{28\times 20}{28+20}=11.67\Omega[/tex]

So we have resistor with 11.67Ω in a 120 V source of voltage.

We have equation V = IR

Substituting

               120 = I x 11.67

                 I = 10.29 A

The total current supplied by the source of voltage = 10.29 A

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