Respuesta :
The distance at which the puck of mass 0.13 kg, traveling across the ice at speed 17.4 m/sec will stop is 131.2 meters.
Given to us
Mass of the puck, m = 0.13kg
The velocity of the ice, u = 17.4 m/sec
Friction force, f = 0.15 N
What is the final velocity of the puck?
We know we want to stop the puck, therefore, the final velocity of the puck will be 0.
v = 0
What is the deceleration of the puck?
We know that according to the first law of motion,
Force = mass x acceleration
F = m x a
Substitute the value,
[tex]0.15 = 0.13 \times a[/tex]
[tex]a = 1.1538\rm\ m/s^2[/tex]
As we know that the final velocity of the puck will be 0, therefore, there will be a deceleration in the puck.
a = -1.1538 m/s².
Thus, the acceleration of the ice puck is -1.1538 m/s².
What is the stopping distance for this puck?
We know that according to the third equation of the motion,
[tex]v^2-u^2 = 2as[/tex]
substitute the values,
[tex]0^2-(17.4)^2 = 2(-1.1538)s[/tex]
s = 131.2012 = 131.2 meters
Hence, the distance at which the puck of mass 0.13 kg, traveling across the ice at speed 17.4 m/sec will stop is 131.2 meters.
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