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Motor oil, with a viscosity of 0.25 N ∙ s/m 2, is flowing through a tube that has a radius of 5.0 mm and is 25 cm long. The drop in pressure is 300 kPa. What is the volume of oil flowing through the tube per second?

Respuesta :

Answer:

1.18 x 10^-3 m^3/s

Explanation:

η = 0.25 N s/m^2, radius, r = 5 mm = 0.005 m, l = 25 cm = 0.25 m

P = 300 kPa = 300,000 Pa, Volume of flow = ?

By use of Poiseuillie's equation

Volume of flow = π P r^4 / (8 η l)

Volume of flow = (3.14 x 300000 x 0.005^4) / (8 x 0.25 x 0.25)

Volume of flow = 1.18 x 10^-3 m^3/s

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