Answer:
The work done by the steam is 213 kJ.
Explanation:
Given that,
Mass = 5 kg
Pressure = 150 kPa
Temperature = 200°C
We need to calculate the specific volume
Using formula of work done
[tex]W=Pm\DeltaV[/tex]
[tex]W=Pm(\dfrac{RT_{1}}{P_{atm}}-\dfrac{RT_{2}}{P_{atm}}[/tex]
[tex]W=\dfrac{PmR}{P_{atm}}(T_{2}-T_{1})[/tex]
Where,R = gas constant
T = temperature
P = pressure
[tex]P_{atm}[/tex]=Atmosphere pressure
m = mass
Put the value into the formula
[tex]W=\dfrac{150\times10^{3}\times5\times287.05}{1.01\times10^{5}}\times(473-373)[/tex]
[tex]W=213\ kJ[/tex]
Hence, The work done by the steam is 213 kJ.
