Which of the following reveals the minimum value for the equation 2x2 − 4x − 2 = 0?

2(x − 1)2 = 4
2(x − 1)2 = −4
2(x − 2)2 = 4
2(x − 2)2 = −4

Respuesta :

Answer:

[tex]2(x-1)^{2}=4[/tex]

Step-by-step explanation:

we have

[tex]2x^{2} -4x-2=0[/tex]

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

Group terms that contain the same variable and move the constant to the other side

[tex]2x^{2} -4x=2[/tex]

Factor the leading coefficient

[tex]2(x^{2} -2x)=2[/tex]

[tex]2(x^{2} -2x+1)=2+2[/tex]

[tex]2(x^{2} -2x+1)=4[/tex]

Rewrite as perfect squares

[tex]2(x-1)^{2}=4[/tex] -----> this is the answer

The vertex is the point (1,-4)

Answer:

2(x - 1)2 =4

Step-by-step explanation:

Got a 100%

Good luck :)