Answer:
Total energy, [tex]TE=3.006\times 10^{-10}\ J[/tex]
Explanation:
It is given that, a proton in a certain particle accelerator has a kinetic energy that is equal to its rest energy. Let KE is the kinetic energy of the proton and E₀ is its rest energy. So,
[tex]KE=E_o[/tex]
The total energy of the proton is equal to the sun of kinetic energy and the rest mass energy.
[tex]TE=KE+E_o[/tex]
[tex]TE=2E_o[/tex]
[tex]TE=2m_{proton}c^2[/tex]
[tex]TE=2\times 1.67\times 10^{-27}\ kg\times (3\times 10^8\ m/s)^2[/tex]
[tex]TE=3.006\times 10^{-10}\ J[/tex]
So, the total energy of the proton as measured by a physicist working with the accelerator is [tex]3.006\times 10^{-10}\ J[/tex]
