Answer:
0.66276.
Step-by-step explanation:
We are asked to find the approximate value of p(z<0.42) for a standard normal distribution.
Our given expression means the probability of getting a z-score less than 0.42.
We need to find the probability of getting the area corresponding to a z-score less than 0.42 under normal distribution curve.
We will normal distribution table to solve our given problem.
[tex]p(z<0.42)=0.66276[/tex]
Therefore, the approximate value of our given expression would be 0.66276.
