The value for Kw is 1.0 x 10-14 at 298K, but this value is temperature dependent. Given what you know about Kw and acid/base chemistry, what will the pH of water be at 303K if the value for Kw is 1.47 x 10-14? Is this solution acidic, basic, or neutral?

Respuesta :

znk

Answer:

6.92; neutral

Explanation:

Kw = [H^+][OH^-] = 1.47 × 10^-14

pKw = pH + pOH = 13.83

At neutrality, [H^+] = [OH^-] and pH = pOH

2pH = 13.83

 pH =  6.92

The pH will be 6.92.

At 303 K, this will be the neutral pH, because [H^+] = [OH^-]

The pH of the water will be 6.92 and the solution will be neutral.

What is pH?

pH value determined how basic or acidic a solution is.

The meaning of pH is potential hydrogen.

By the formula:

[tex]\bold{Kw = [H^+][OH^-]}[/tex]

[tex]\bold{1.47 \times10^-14}[/tex]

[tex]\bold{pKw = pH + pOH = 13.83}[/tex]

[tex]\bold{At\; neutrality, [H^+] = [OH^-]\; and\; pH = pOH}[/tex]

[tex]2pH = 13.83\\pH \;\;=6.92[/tex]

Thus, the pH will be 6.92 and the solution will be neutral.

Learn more about pH, here:

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