d = sqrt (2-(-6))² + (-3-4)²)
d = sqrt ( 8² + 7² )
d = sqrt ( 64 + 49 )
d = sqrt (113)
Answer: The distance between the two points is roughly 10,63:
B)
The distance between the points (2,-3) and (-6,4) on the coordinate plane is 10.63 units. This can be obtained by using the distance formula.
The distance between two points (x₁,y₁) and (x₂,y₂) is
d = [tex]\sqrt{{(x_{2}-x_{1} )}^{2} + (y_{2}-y_{1} )^{2}[/tex]
In the given question, (x₁,y₁) is (2,-3) and (x₂,y₂) is (-6,4),
the distance d = [tex]\sqrt{{(x_{2}-x_{1} )}^{2} + (y_{2}-y_{1} )^{2}[/tex]
=[tex]\sqrt{{((-6)-2 )}^{2} + (4-(-3) )^{2}[/tex]
=[tex]\sqrt{{(-8)}^{2} + (7 )^{2}[/tex]
= [tex]\sqrt{{64 + 49[/tex]
=√113 =10.63 units
Hence the distance between the points (2,-3) and (-6,4) on the coordinate plane is 10.63 units. Thus option B is correct.
Learn more about distance formula here:
brainly.com/question/14074444
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