Membrane walls of living cells have surprisingly large electric fields across them due to separation of ions. What is the voltage across an 8.47-nm-thick membrane if the electric field strength across it is 8.76 MV/m? You may assume a uniform E-field.

Respuesta :

Answer:

Voltage, V = 0.0741 volts

Explanation:

It is given that,

Width of membrane, [tex]d=8.47\ nm=8.47\times 10^{-9}\ m[/tex]

Electric field strength, [tex]E=8.76\ MV/m=8.76\times 10^6\ V/m[/tex]

We need to find the voltage across membrane. Electric field is given by :

[tex]E=\dfrac{V}{d}[/tex]

[tex]V=E\times d[/tex]

[tex]V=8.76\times 10^6\ V/m\times 8.47\times 10^{-9}\ m[/tex]

V = 0.0741 V

So, the voltage across the membrane is 0.0741 volts. Hence, this is the required solution.