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1) none of these ions ( Fe²⁺ , Fe³⁺ , Mn²⁺ 0 have any electrons in the 4s subshell . ( TRUE )
2) Fe²⁺ is more paramagnetic ( has more unpaired electrons ) than Fe³⁺.
( FALSE ) explanation :
* Fe²⁺ has no free electrons and is diamagnetic
* Fe³⁺ has one unpaired electron and is paramagnetic
3) Fe³⁺ is isoeletronic with Mn²⁺ . ( TRUE )
4) Fe has 2 outer electrons , 8 valence electrons , and 18 core eletrons. (TRUE )
electron configuration Fe = 1s², 2s², 2p⁶, 3s² , 3p⁶, 4s² , 3d⁶ or :
[Ar] = 4s² , 3d⁶
5) Fe³⁺ is predicted to be a stronger potencial oxidizing agent ( can be reduced more ) than Fe²⁺ ( TRUE )
Hope this helps!
The false statement is that; "Fe2+ is more paramagnetic (has more unpaired electrons) than Fe3+."
Iron is a transition element that has 26 valence electrons in the ground state. The ground state electron configuration of iron is [Ar] 3d6 4s2. The 4s electrons are the outer electrons hence Fe2+ is a d6 specie while Fe3+ is a d5 specie.
This means that Fe3+ has five unpaired electrons while Fe2+ has only four unpaired electrons. Hence, the false statement is that; "Fe2+ is more paramagnetic (has more unpaired electrons) than Fe3+."
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