Select the false statement below : Fe2+ is more paramagnetic (has more unpaired electrons) than Fe3+ Fe3+ is isoelectronic with Mn2+ Fe has 2 outer electrons, 8 valence electrons, and 18 core electrons Fe3+ is predicted to be a stronger potential oxidizing agent (can be reduced more) than Fe2+ none of these ions (Fe2+, Fe3+, Mn2+) have any electrons in the 4s subshell

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1) none of these ions ( Fe²⁺ , Fe³⁺ , Mn²⁺ 0 have any electrons in the 4s subshell .  ( TRUE )

2) Fe²⁺ is more paramagnetic ( has more unpaired electrons ) than Fe³⁺.

( FALSE )  explanation :

* Fe²⁺ has no free electrons and is diamagnetic

* Fe³⁺ has one unpaired electron and is paramagnetic

3) Fe³⁺ is isoeletronic with Mn²⁺ . ( TRUE )

4) Fe has 2 outer electrons , 8 valence electrons , and 18 core eletrons. (TRUE )

electron configuration  Fe = 1s², 2s², 2p⁶, 3s² , 3p⁶, 4s² , 3d⁶ or :

[Ar] = 4s²  , 3d⁶

5) Fe³⁺ is predicted to be a stronger potencial oxidizing agent  ( can be reduced more ) than Fe²⁺   ( TRUE )

Hope this helps!

The false statement is that; "Fe2+ is more paramagnetic (has more unpaired electrons) than Fe3+."

Iron is a transition element that has 26 valence electrons in the ground state. The ground state electron configuration of iron is [Ar] 3d6 4s2. The 4s electrons are the outer electrons hence Fe2+ is a d6 specie while Fe3+ is a d5 specie.

This means that Fe3+ has five unpaired electrons while Fe2+ has only four unpaired electrons. Hence, the false statement is that; "Fe2+ is more paramagnetic (has more unpaired electrons) than Fe3+."

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