Respuesta :
Answer:
The Lewis structures are in image attached.
Explanation:
Lewis symbol is a representation of an element symbol along with its valence electrons around it in the form of dot(s).
Mono-atomic ions formed from the following :
(a) Cl
Chlorine's atomic number is 17 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet
[tex]Cl=1s^22s^22p^63s^23p^5[/tex]
[tex]Cl^-=1s^22s^22p^63s^23p^6[/tex]
(b) Na
Sodium's atomic number is 11 in which only 1 electrons are present in its valence shell .So in order to gain noble gas stability it will loose 1 electron to completes its octet. In the Lewis symbol no dot shown as sodium has lost its 1 electron.
[tex]Na=1s^22s^23p^63s^1[/tex]
[tex]Na^+=1s^22s^23p^63s^0[/tex]
(c) Mg
Magnesium's atomic number is 12 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electrons to completes its octet.
In the Lewis symbol no dot shown as magnesium has lost its 2 electrons.
[tex]Mg=1s^22s^23p^63s^2[/tex]
[tex]Mg^{2+}=1s^22s^23p^63s^0[/tex]
(d)Ca
Calcium's atomic number is 20 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.
In the Lewis symbol no dot shown as calcium has lost its 2 electron.
[tex]Ca= 1s^22s^22p^63s^23p^64s^2[/tex]
[tex]Ca^{2+}=1s^22s^23p^6^23p^64s^0[/tex]
(e) K
Potassium's atomic number is 19 in which only 1 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 1 electron to completes its octet.
In the Lewis symbol no dot shown as calcium has lost its 1 electron.
[tex]K= 1s^22s^22p^63s^23p^64s^1[/tex]
[tex]K^{+}=1s^22s^23p^6^23p^64s^0[/tex]
(f) Br
Bromine's atomic number is 35 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet
[tex]Br=1s^22s^22p^63s^23p^63d^{10}4s^24p^5[/tex]
[tex]Br^-= 1s^22s^22p^63s^23p^63d^{10}4s^24p^6[/tex]
(g) Sr
Strontium's atomic number is 38 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.
In the Lewis symbol no dot shown as calcium has lost its 2 electron.
[tex]Sr=1s^22s^22p^63s^23p^63d^{10}4s^24p^65s^2[/tex]
[tex]Sr^{2+}=1s^22s^22p^63s^23p^63d^{10}4s^24p^65s^0[/tex]
(h) F
Florine's atomic number is 7 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet.
[tex]F=1s^22s^22p^5[/tex]
[tex]F^-=1s^22s^22p^6[/tex]
