Answer:
9.2 grams of ethanol should be added.
Explanation:
Let the mass of ethanol be x
Density of an ethanol = [tex]d_1=0.80 g/cm^3[/tex]
Volume of the ethanol =[tex]V_1=\frac{x}{0.80 g/cm^3}[/tex]
Mass of chloroform = 5.0 g
Density of an chloroform= [tex]d_2=1.5 g/cm^3[/tex]
Volume of the ethanol =[tex]V_2=\frac{5.0 g}{1.5 g/cm^3}=\frac{1}{3}[/tex]
Mass of the mixture,m = x + 5.0 g
Density of the mixture = [tex]d=1.2 g/cm^3[/tex]
Volume of the mixture=[tex]V=\frac{m}{1.2 g/cm^3}=\frac{x+5.0 g}{1.2 g/cm^3}[/tex]
[tex]V=V_1+V_2[/tex]
[tex]\frac{x+5.0 g}{1.2 g/cm^3}=V_1+\frac{1}{3}[/tex]
[tex]\frac{x+5.0 g}{1.2 g/cm^3}=\frac{x}{0.80 g/cm^3}+\frac{1}{3}[/tex]
Solving for x , we get
x = 9.2 g
9.2 grams of ethanol should be added.
