Answer:
Velocity of the particle at time t = a
[tex]v(a)=-\frac{12}{a^3}[/tex]
Velocity of the particle at time t = 1
[tex]v(1)=-12m/s[/tex]
Velocity of the particle at time t = 2
[tex]v(2)=-1.5m/s[/tex]
Velocity of the particle at time t = 3
[tex]v(3)=-0.44m/s[/tex]
Explanation:
Displacement,
[tex]s(t)=\frac{6}{t^2}[/tex]
Velocity is given by
[tex]v(t)=\frac{ds}{dt}=\frac{d}{dt}\left ( \frac{6}{t^2}\right )=-\frac{12}{t^3}[/tex]
Velocity of the particle at time t = a
[tex]v(a)=-\frac{12}{a^3}[/tex]
Velocity of the particle at time t = 1
[tex]v(1)=-\frac{12}{1^3}=-12m/s[/tex]
Velocity of the particle at time t = 2
[tex]v(2)=-\frac{12}{2^3}=-1.5m/s[/tex]
Velocity of the particle at time t = 3
[tex]v(3)=-\frac{12}{3^3}=-0.44m/s[/tex]