Respuesta :
[tex]\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} h=height\\ r=radius\\ \cline{1-1} h=16\\ r=7 \end{cases}\implies SA=2\pi (7)(16+7) \\\\\\ SA=14\pi (23)\implies SA=322\pi[/tex]
The surface area of the right circular cylindrical container that has a radius of 7 cm and a height of 16 cm in terms of π is 322π. This is obtained by using the formula for surface area of cylinder.
What is the surface area ?
Surface area of cylinder is, S = 2πrh+2πr², where S is the surface area, r is the radius and h is the height of the cylinder.
Given that r =7 cm, h =16 cm,
S = 2πrh+2πr²
= 2π(7)(16)+2π(7)²
= 224π+98π
= 322π
Hence the surface area of the right circular cylindrical container that has a radius of 7 cm and a height of 16 cm in terms of π is 322π.
Learn more about surface area of cylinder here:
brainly.com/question/18440876
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