Answer:
electrical conductivity is given as
[tex]\sigma = 3.8 \times 10^{-15} [/tex]
Explanation:
For a current carrying conductor we will have relation between current density and electric field inside the conductor as
[tex]j = \sigma E[/tex]
here we have
current density = j
electric field = E
given that
[tex]j = 7.00 \times 10^{-13}[/tex]
[tex]E = 185 V/m[/tex]
now we will have
[tex]\sigma = \frac{j}{E}[/tex]
[tex]\sigma = \frac{7.00 \times 10^{-13}}{185}[/tex]
[tex]\sigma = 3.8 \times 10^{-15} [/tex]
