Answer:
Part a)
W = 16.7 N
Part b)
r = 2.45 R
Explanation:
Part a)
As we know that acceleration due to gravity on the surface of moon is 1/6 times the gravity on the surface of earth
So the force due to gravity will decrease by the factor of 6
so we will have
[tex]W_{moon} = \frac{1}{6}W_{earth}[/tex]
[tex]W_{moon} = \frac{1}{6}(100)[/tex]
[tex]W_{moon} = 16.7 N[/tex]
Part b)
For the same value of the weight as the surface of moon the acceleration due to gravity of earth must be 1/6 times
so we have
[tex]\frac{GM}{r^2} = \frac{GM}{6R^2}[/tex]
[tex]r^2 = 6R^2[/tex]
[tex]r = 2.45 R[/tex]