Answer:
0.45 m
Explanation:
m = 1.23 kg, k = 37.4 N/m, vmax = 2.48 m/s
velocity is maximum when it passes through the mean position.
[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex]
[tex]T = 2\pi \sqrt{\frac{1.23}{37.4}}[/tex]
T = 1.139 sec
w = 2 π / T
w = 2 x 3.14 / 1.139
w = 5.51 rad / s
Vmax = w A
Where, A be the amplitude
2.48 = 5.51 A
A = 2.48 / 5.51 = 0.45 m
