Answer:
Force, F = 16814.95 N
Explanation:
It is given that,
Mass of space station, m = 2010 kg
Altitude, [tex]d=5.35\times 10^5\ m[/tex]
Mass of earth, [tex]m=5.98\times 10^{24} kg[/tex]
Mean radius of earth, [tex]r=6.37\times 10^6\ m[/tex]
Magnitude of force is given by :
[tex]F=G\dfrac{Mm}{R^2}[/tex]
R = r + d
[tex]R=6.37\times 10^6\ m+5.35\times 10^5\ m=6905000\ m[/tex]
[tex]F=6.67\times 10^{-11}\times \dfrac{2010\ kg\times 5.98\times 10^{24} kg}{(6905000\ m)^2}[/tex]
F = 16814.95 N
So, the force between the space station and the Earth is 16814.95 N. Hence, this is the required solution.
