Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
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We have the points (-1, -4) and (1, 6). Substitute:
[tex]m=\dfrac{6-(-4)}{1-(-1)}=\dfrac{10}{2}=5[/tex]
[tex]y-(-4)=5(x-(-1))\\\\y+4=5(x+1)[/tex]
Convert it to the standard form [tex]Ax+By=C[/tex]:
[tex]y+4=5(x+1)[/tex] use the distributive property
[tex]y+4=5x+5[/tex] subtract 4 from both sides
[tex]y=5x+1[/tex] subtract 5x from both sides
[tex]-5x+y=1[/tex] change the signs
[tex]5x-y=-1[/tex]